# Number converter in Python

Just because I was set this challenge this morning, I have written my first attempt at a number converter in Python 3. You simply pass a positive integer and the program returns that number in words.

For example, if you pass 1234, it will return "one thousand two hundred and thirty-four".

The program works for all positive integers up to ten to the power 48, which should be good enough for most practical purposes.

The code is listed below, or you can download it from OneDrive.

``` def numberConvert( num ):    # pass a string containing a positive integer    # will return the number as a string of words    # for example 1234 will return    # "one thousand two hundred and thirty-four"    number = str(num)    digitlist = []    groupedlist = []        for digit in number:        digitlist.append(digit)    #puts text into grouped list eg    #567893 --> ['893', '567']    while len(digitlist)>0:        s = ""        c = 0        while c<3 and len(digitlist)>0:            s = s + digitlist.pop()            c += 1        groupedlist.append(s[::-1])     out = ""    power = 0    a = ["thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion", "spetillion", "octillion", "nonillion", "decillion", "undecillion", "duodecillion", "tredecillion", "quattuordecillion", "quidecillion"]    for item in groupedlist:        if power >0:            out = parseNumber(item) + " "+ a[power-1] + " "+out        else:            out = parseNumber(item)        power += 1    return out def parseNumber( number ):    #pass a 3 digit string , eg '456'    if len(number) == 1:        return(parseDigit(number))    elif len(number) == 3:        if number[0:1] != '0':            if int(number[1:3]) != 0:                return(parseDigit(number[0:1])+" hundred and "+parseTwoDigit(number[1:3]))            else:                return(parseDigit(number[0:1])+" hundred ")        else:            if int(number[1:3]) != 0:                return("and "+parseTwoDigit(number[1:3]))            else:                return(parseTwoDigit(number[1:3]))    else:        return(parseTwoDigit(number))               def parseDigit( number ):    #deals with one digit numbers    a = ['', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine']    return a[int(number)] def parseTwoDigit( number ):    #deals with two digit numbers    a = ['twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']    b = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen']    if (number[0:1]) == '1':        return(b[int(number[1:2])])    elif (number[0:1]) == '0':        return(parseDigit(number[1:]) )    else:        if number[1:] != '0':            return(a[int(number[0:1])-2]+ "-" +parseDigit(number[1:]) )        else:            return(a[int(number[0:1])-2]) #test programwhile True:    num = int(input("Enter integer: "))    print(numberConvert(num))```